Math, asked by shivpratap9, 10 months ago

(v) x² + 4x + 5 = 0

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Answered by Priyanshu1singh

Answer:

Step-by-step explanation:

X=1&5

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Answered by abdul9838

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$\huge \bf \: hola \\ \\ \bf hey \: user \: here \: is \: ans \\ \\ \huge \bf \: solution \\ \\ \bf {x}^{2} + 4x + 5 = 0 \\ \\ \bf \: let \: start \\ \\ \huge \bf \: method \\ \bf \: completing \: square \: method \\ \\ \bf \: ( {x)}^{2} + 2 \times x \times 2 + {2}^{2} - {2}^{2} + 5 = 0 \\ \\ \bf \: (x + 2)^{2} - 4 + 5 = 0 \\ \\ \bf \: (x + 2)^{2} + 1 = 0 \\ \\ \bf \: x + 2 = \pm \: \sqrt{1} \\ \\ \bf \: x = - 2 - 1 \\ \\ \bf \: x = - 3 \\ \\ \bf \: and \\ \\ \bf \: x = 1 - 2 \\ \\ \bf \: x = - 1 \: \: \: ans \\ \\$

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$\boxed{ \bf \: thanks \: for \: asking} \\ \boxed{ \huge \: \bf \: follow \: me} \\ \boxed{ \bf \: abdul \: is \: here}$

tanishka90: ok

tanishka90: try

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(v) x² + 4x + 5 = 0