Question

V1, V2 and V3 are the p.ds. across the 1Ω, 2Ω and 3Ω resistors in the following diagram, and the current is 5 A.
Which one of the columns (a) to (d) shows the correct values of V1, V2 and V3 measured in volts?
V1
V2
V3
(a)
1.0
2.0
3.0
(b)
5.0
10.0
15.0
(c)
5.0
2.5
1.6
(d)
4.0
3.0
2.0; V1, V2 and V3 are the p.ds. across the 1Ω, 2Ω and 3Ω resistors in the following diagram, and the current is 5 A.
Which one of the columns (a) to (d) shows the correct values of V1, V2 and V3 measured in volts?

Answer 1

V1= 5.0, V2= 10.0, V3= 15.0, It means, the current flowing through each resistor is same.

Explanation:  

From the diagram, it is clear that the resistors are connected in series. It means, the current flowing through each resistor is same.

Given: $R1 = 1\Omega, R2= 2\Omega, R3= 3\Omega and I= 5A$

So, from the Ohm’s law, we get

                      V = IR

Now,  

         $V1 = IR1= 5A\times 1\Omega = 5 V$

         $V2 = IR2 = 5A\times 2\Omega = 10 V$

        $V3= IR3= 5A\times 3\Omega= 15 V$

You can get all the answers of Chapter 1 in the link below:

https://brainly.in/question/14961133

Few questions related to this chapter:

A battery and three lamps are connected as shown

Which of the following sta.....

brainly.in/question/14914587

In the circuit shown belowΏ

The potential difference across the 3 Ω resist.....

brainly.in/question/14914590

Answer 2

Answer:

V1= 5.0, V2= 10.0, V3= 15.0, It means, the current flowing through each resistor is same.

Explanation:

From the diagram, it is clear that the resistors are connected in series. It means, the current flowing through each resistor is same.

Given: R1 = 1\Omega, R2= 2\Omega, R3= 3\Omega and I= 5AR1=1Ω,R2=2Ω,R3=3ΩandI=5A

So, from the Ohm’s law, we get

V = IR

Now,

V1 = IR1= 5A\times 1\Omega = 5 VV1=IR1=5A×1Ω=5V

V2 = IR2 = 5A\times 2\Omega = 10 VV2=IR2=5A×2Ω=10V

V3= IR3= 5A\times 3\Omega= 15 VV3=IR3=5A×3Ω=15V

pls mark me as brainleast