Math, asked by preetibahukhandi1, 8 months ago

v2 cosec 20° sec 20 =​

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Answered by Legend42
14

Answer:

Answer . Let I=3 cosec 20−sec20. =sin203 −cos201.

Let I = √(3) cosec 20 - sec20 = √(3)sin20 - 1cos20 = √(3)cos20-sin20sin20cos20 = 4[ √(3)2cos20- sin2022sin20cos20 ] = 4[ cos30cos20-sin30sin20sin(40)+s

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