v2/r=g ye formula kha se he . kis article se .
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It is from Vertical Circular Motion.
This the minimum value of centripetal or radial acceleration.
At the topmost point of VCM.
min. centripetal force = mg
therefore, (mv²)/r = mg
hence, v²/r=g
Hope It helped You!
edit: For example, consider a pendulum being whirled in a vertical circle.
the forces on the bob at the top most point: Mg and Tenstion(T)
so, F(cp) = Mg + T
so min.F(cp) = Mg
because there may be a situation when the tension on the string may become zero... but the weight of the bob cannot disappear.
I suggest you analyse the situation when a car moves on a overhead bridge and is at its topmost point too.
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