Question

v²-u²=2as derive by integration method

Answer 1

Solving for a body under constant acceleration, for a displacement 0 to s,

(initial velocity=u, final velocity=v)

a = dV/dT

multiply divide by dS

a= dV/dS * dS/dT

dS/dT is equal to velocity ( rate of change of displacement)

a= dV/dS * V

a*dS = V*dV

Integrate both sides

(P.S: integreal signs as well as limits aren't possible in the keyboard)

(Integral x = x^2/2)

(a constant)
(Integral dS = s)

[V^2/2] (limit u to v) = a [S] (limit 0 to s)

V^2/2 — U^2/2 = a ( s-0)

V^2 — U^2 = 2as

V^2 = U^2 + 2a
Hope this helps you..

Answer 2

heya...

Here is your answer....