व्यंजक (4x3 +8x2-4x-7) को (2x + 1) से भाग देने पर
शेषफल ज्ञात कीजिए।
Answers
Given : व्यंजक (4x³ +8x²-4x-7) को (2x + 1) से भाग
To Find : शेषफल
Solution:
2x² + 3x - 7/2
(2x + 1) (4x³ +8x²-4x-7)
4x³ +2x²
_______
6x²-4x-7
6x² + 3x
_________
-7x - 7
-7x - 7/2
_________
- 7/2
शेषफल = - 7/2
Method 2
2x + 1 = 0 => x = - 1/2
4x³ +8x²-4x-7
substitute x = -1/2
= 4(-1/2)³ + 8(-1/2)² - 4(-1/2) - 7
= -1/2 + 2 + 2 - 7
= -1/2 - 3
= -7/2
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