Math, asked by mesbilifelkopandey, 1 year ago

व्यंजकों का गुणनखंड
x2+ 8x+16

Answers

Answered by nishuuuu
3
x2+8x+16
x2+4x+4x+16=0
x(x+4)+4(x+4)=0
(x+4)(x+4)=0
x+4=0
x=-4
Answered by shivam5566677pef3pn
2

 {x }^{2}  + 8x + 16 \\  {x}^{2}  + 4x + 4x + 16   \\  {x}(x + 4) + 4(x + 4) \\ (x + 4)(x + 4)
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