valasa kuli poem in own words
Answers
Answer:
poem
Explanation:
This is very similar to yesterday's problem, except this time we have a sum rather than a product to deal with. But we'll approach it the same way, and try the first few in order to see a pattern:
1/(1x2) = 1/2
1/(1x2) + 1/(2x3) = 1/2 + 1/6 = 3/6 + 1/6 = 4/6 = 2/3
1/(1x2) + 1/(2x3) + 1/(3x4) = 2/3 + 1/12 = 8/12 + 1/12 = 9/12 = 3/4
1/(1x2) + 1/(2x3) + 1/(3x4) + 1/(4x5) = 3/4 + 1/20 = 15/20 + 1/20 = 16/20 = 4/5
and so on...
In doing the calculations above, we took advantage of the fact that to do a given sum, we had already done the previous one and could use the result of the previous calculation.
There is certainly a pattern in the answers so far! And from the pattern we can infer that the answer to our problem is (probably) 99/100.
To understand better what is going on, we need to re-express the terms in the sum as follows:
1/(1x2) = 1/2 = 1/1 - 1/2
1/(2x3) = 1/6 = 1/2 - 1/3
1/(3x4) = 1/12 = 1/3 - 1/4
and so on...
This pattern always works, since 1/n - 1/(n+1) = (n+1)/(n(n+1)) - n/(n(n+1)) = 1/(n(n+1)).
And we can use this pattern to rewrite our sum as follows:
1/(1x2) + 1/(2x3) + 1/(3x4) + 1/(4x5) + ... = (1/1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) +...
The first 1 in the 1/1 - 1/2 will always be there, then there will be a lot of cancellation, and then the very last thing subtracted will "survive".
This shows that the sum up to 1/(n(n+1)) is 1 - 1/(n+1). So our sum really is 1 - 1/100 = 99/100.