value of (1+i
)^n+(1-i)^n is ____if n is positive integer
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Answer:
k=2
Step-by-step explanation:
(1−i) n (1− i 1 ) n =(1−i) n (1+(i) 2 ⋅ i 1 ) n =(1−i) n (1+i) n ={(1−i)(1+i) n }=(1−i 2 ) n =2 n
Comparing with k n
We get k=2
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