Question

value of 3√(64)^-2?​

Answer 1

Step-by-step explanation:

$\implies$ $3\sqrt{(64)}^{-2}$

$\implies$ $3×8^{-2}$

$\implies$ $3×\Large\frac{1}{8^{2}}$ $(a^{-m}=\Large\frac{1}{a^{m}}$)

$\implies$ $\Large\frac{3}{64}$

$\implies$ $\boxed{0.046875}$

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Answer 2

Answer:

0.046875

Let's solve this step by step :

$3 \sqrt{ {64}^{ - 2} }$

First we simplify the root --->

√64^(-2)

For this, we must reduce the index of the radical and exponent with 2

| 64^(-1) |

Now calculate the absolute value. Which is always positive.

| 64^(-1) |

64^(-1)

Now let's get back to the question.

$3 \sqrt{ {64}^{ - 2} }$

=

$3 \times {64 }^{ - 1}$

= 3 * 1/64

= 3/64 = 0.046875

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Hope it helps you