Math, asked by tisrisu, 1 year ago

value of (5x^-3yz^2)^-2

Answers

Answered by Anonymous
25

Answer:

\left(5x^{-3}yz^2\right)^{-2} = 5^{-2}x^{6}y^{-2}z^{-4} = \dfrac{x^6}{5^2y^2z^4} = \dfrac{x^6}{25y^2z^4}

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