value of a.
5. Find the zeros of the p(x) = (x – 3) (x + 2).
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Answer:
of x when p(x)=0
⇒ x
3
−x=0
⇒ x(x
2
−1)=0
⇒ x(x−1)(x+1)=0
⇒ x=0,1,−1
Hence zeroes of p(x) are 0,1,−1.
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