Question

Value of cfse, in tetrahedral complex having 3 d 4 configuration of metal ion, surrounded by weak field ligands, will be

Answer 1

Answer:

Chxyi

Explanation:

Regards

Answer 2

Given:

1. The complex has a tetrahedral geometry.
2. The complex has a 3d₄ configuration.
3. The complex is surrounded by weak field ligands.

To find:

The CFSE of the complex.

Solution:

• In tetrahedral splitting the two e-orbitals are lowered in energy by 0.6Δt and the three t₂ orbitals has a 0.4Δt increase in their energies.
• Since the complex is weak field in nature, there will be no pairing of electrons unless all the d-orbitals are singly-occupied.
• Hence, the complex has e², t₂² configuration.
• Therefore the CFSE will be equal to -0.4Δt (2×(-0.6Δt) + 2×(0.4Δt)).
• We know that Δt= 4/9Δo, hence CFSE = -0.177Δo

Answer:

The CFSE for the given complex is equal to -0.4Δt or -0.177Δo.