Question

Value of current at resonance in a series rlc is affected by the value of

Answer 1

Explanation:

Answer:

For a RLC circuit,

\(Z = R + j\left( {{X_L}-{X_C}} \right)\)

At resonance, \({X_L} = {X_C}\)

\( \Rightarrow Z = R\)

\(I = \frac{V}{Z} = \frac{V}{R}\)

Hence the value of current at resonance in a series RLC circuit is affected by the value of resistance only.

Answer 2

Answer:

R only

Explanation: We know $Z=\sqrt{R^{2} +(Xc-Xl)^{2}$

         At resonance Xl =Xc, Hence Z = R

         Also $I = \frac{V}{Z} = \frac{V}{R}$

         so $I \alpha \frac{1}{R}$