Question

value of iota,iota²,iota³,iota⁴
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Answer 1

$\purple{\huge{\bold{\mathcal{Answer}}}}$

$i = \sqrt{ - 1} \\ i {}^{2} = - 1 \\ i {}^{3} = (i) {}^{2} (i) = ( - 1)(i) = - i \\ i {}^{4} = i {}^{2} \times i {}^{2} = ( - 1) \times ( - 1) = 1$

Answer 2

Explanation:

i= −1

i² =−1

i³ =(i)²(i)=(−1)(i)

=−i4 =i²×i²

=(−1)×(−1)=1

now,

i+i²+i³+i⁴= i+-1+-i+1

= 0