Question

Value of K, if linear equations 3x + 2y =5.and 12 x - Ky =7 have no solution
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Answer 1

Answer:

a1= k+1

b1 = 2

a2=3

b2=k

in no solution case

a1/a2 = b1/b2 not = c1/c2

k+1/3 = 2/k

k(k+1)=3×2

{k}^{2} + k = 6k

2

+k=6

or

so \: {k}^{2} + k - 6 = 0sok

2

+k−6=0

or

{k}^{2} + 3k \: - 2k - 6 = 0k

2

+3k−2k−6=0

or

k(k+3) -2(k+3)=0

(k-2)(k+3)=0

so k=2 or k=-3

hope it helps you