Question

value of k of kx-y=2 and 6x-2y=3 has unique solution

Answer 1

Here is your answer ⤵⤵⤵

a1/a2 = k/6

b1/b2 = -1/-2

= 1/2

Since, these equations have a unique solution.

a1/a2 is not equal to b1/b2

=> k/6 is not equal to 1/2

=> k is not equal to 1×6/2

=> k is not equal to 3

Therefore, except 3 , k can have all values.

HOPE IT HELPS YOU ☺☺ !!!

Answer 2

kx-y=2              and             6x-2y=3

since the given two eq.s have unique soln.

therefore,

a1/a2≠b1/b2

k/6≠ -1/-2

k/6≠ 1/2

2k≠ 6

k ≠3