value of log8+log1/8
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Answered by
3
Answer:
Hey Buddy here's ur answer
0 is the answer
Step-by-step explanation:
As we know,
log(a/b)= log(a)-log(b)
Then, log1/8= log1- log8
So, logo+log1/8 =log8+log1-log8
Here, both the log8 will be cancelled out due to of opposite sign & same value.
Hence, log8+log1/8=log1= 0 Ans. [Since, log1=0].
Mark me brainliest.
Answered by
2
log8+log1/8=log(8×1/8)=log1=0; as logx+logy=logxy, Please mark the answer as brainliest.
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