Math, asked by ayethandarphyo2001, 3 days ago

Value of machine depreciates every year at 15%. If its present value is Ks. 480000, what will be its value after 3 years?​

Answers

Answered by mathdude500
28

Question :-

Value of machine depreciates every year at 15%. If its present value is Rs. 480000, what will be its value after 3 years?

\large\underline{\sf{Solution-}}

Given that,

Present value of car, P = Rs 480000

Rate of depreciation, r = 15 % per annum.

Time, n = 3 years

We know,

The depreciated value ( DV, ) received on a certain sum of value depreciated at the rate of r % per annum in n years is given by

\boxed{ \rm{ \:DV \:  =  \: P \:  {\bigg[1 - \dfrac{r}{100} \bigg]}^{n} \: }}  \\

So, on substituting the values, we get

 \rm\:DV \:  =  \: 480000 \:  {\bigg[1 - \dfrac{15}{100} \bigg]}^{3} \:  \\

 \rm\:DV \:  =  \: 480000 \:  {\bigg[ \dfrac{100 - 15}{100} \bigg]}^{3} \:  \\

 \rm\:DV \:  =  \: 480000 \:  {\bigg[ \dfrac{85}{100} \bigg]}^{3} \:  \\

 \rm\:DV \:  =  \: 480000 \:  {\bigg[ \dfrac{17}{20} \bigg]}^{3} \:  \\

\rm\implies \:DV \:  =  \: Rs \: 294780 \\

So, Value of machine depreciates at the rate of 15%, if its present value is Rs. 480000, then its value after 3 years is Rs 294780.

\rule{190pt}{2pt}

Additional Information :-

1. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded annually for n years is given by

\boxed{ \rm{ \:Amount \:  =  \: P \:  {\bigg[1 +  \dfrac{r}{100} \bigg]}^{n} \: }}  \\

2. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded semi - annually for n years is given by

\boxed{ \rm{ \:Amount \:  =  \: P \:  {\bigg[1 +  \dfrac{r}{200} \bigg]}^{2n} \: }}  \\

3. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded 6 for n years is given by

\boxed{ \rm{ \:Amount \:  =  \: P \:  {\bigg[1 +  \dfrac{r}{400} \bigg]}^{4n} \: }}  \\

4. Amount received on a certain sum of money of Rs P invested at the rate of r % per annum compounded monthly for n years is given by

\boxed{ \rm{ \:Amount \:  =  \: P \:  {\bigg[1 +  \dfrac{r}{1200} \bigg]}^{12n} \: }}  \\

Answered by brainpower301
7

PROVIDED INFORMATION :-

Value of machine depreciates every year at 15%. If its present value is rs. 480000

QUESTION :-

Value of machine depreciates every year at 15%. If its present value is rs. 480000, what will be its value after 3 years?

TO FIND :-

what will be its value after 3 years = ?

SOLUTION :-

Present cost of machine = rs 480000

Required cost of machine after 3 years

= 480000 { 1 - 15/100} 3

480000 × 17/20 × 17/20 × 17/20

= rs 294780

value after 3 years = rs 294780

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