Math, asked by sahadhriti28, 3 months ago

Value of p for which (x^2 - 10x + P) is exactly divisible by (x-2) is:

Answers

Answered by amitnrw
1

Given  : (x^2 - 10x + P) is exactly divisible by (x-2)

To find : Value of p

Solution:

Long division method :

                x  - 8

(x-2)   _|   (x^2 - 10x + P) | _

                 x²  - 2x

               ________

                       -8x + p

                       -8x + 16

                    ______

                            p - 16

Remainder must be zero hence

p - 16 = 0

=> p = 16

Method 2 :

divisible by x - 2 hence  x - 2 is a factor          

x -  2 = 0  => x = 2

Substituting x = 2 in expression we must get 0

Hence 2² - 10(2) + p = 0

=> 4 - 20 + p = 0

=> p = 16

Hence Value of p is 16

Learn more:

on dividing x3-3x2+x+2 by a polynomial g(x),the quotient and ...

brainly.in/question/3135153

Divide 9x^3+3x^2-5x+7 by (3x-1) write the quotient and remainder ...

brainly.in/question/6190809

Divide the polynomial (6x³ + 11x² - 10x - 7) by the binomial (2x + 1 ...

brainly.in/question/4743553

Similar questions