Question

Value of p(x) =x^2-3x-4 at x = -1

Answer 1

p(-1) = (-1)^2 - 3(-1) - 4

= 1 + 3 - 4

= 4 - 4

= 0 ans.

hope it's help you ❤❤❤

Answer 2

$p(x)= ( - 1) {}^{2} - 3( - 1) - 4 \\ = 1 + 3 - 4 = 4 - 4 = 0 \\p (x) = 0$