Math, asked by deepaulakh101, 2 months ago

value of sin-1 (1) is_______?​

Answers

Answered by Anonymous
1

Answer:

The given equation is x

2

−8x+15=0

x

2

−8x+15=0

x

2

−5x−3x+15=0

x(x−5)−3(x−5)=0

(x−3)(x−5)=0

x=3,5

Answered by abhi55482
1

Step-by-step explanation:

arc sin 1=arc sin sin pi/2=pi/2. Similarly arc sin 0=arc sin sin 0=0.

Ans: pi/2 & 0

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