value of Sin inverse (sin10)
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your answer is 10
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silu12:
to phir
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Answer:3pi-10
Step-by-step explanation:
as we know, -pi/2 < theta < pi/2
=> -90° < theta < 90°
here, 10 radian=572°
pi=180° 2pi=360° 3pi=540°
hence, 10 radian lies in 3rd quadrant
therefore, sin theta =-ve
-pi/2 <=-[sin^-1 (sin (10-3pi))]<= pi/2
-pi/2 <=3pi-10 <=pi/2
ans=3pi-10
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