Question

Value of sin15?please help me to get answer

Answer 1

Answer:

$\sqrt{3}-1/2\sqrt{2}$

Step-by-step explanation:

sin15 = sin( 45 - 30)

now, Sin( A-B) = sinA cosB - cosA sinB

therefore, Sin(45-30) = sin45 cos 30 - cos45 sin30

= $1/\sqrt{2} *\sqrt{3} /2 - 1/\sqrt{2} *1/2$

$\sqrt{3}-1/2\sqrt{2}$

Answer 2

Step-by-step explanation:

solution:-

i) sin 15⁰

we can write

sin 15⁰= sin(45⁰-30⁰)

now use this formula

sin(A-B)= sinA×cosB- cosA ×sinB

now we can write

sin(45⁰-30⁰)= sin45⁰×cos30⁰-cos45⁰×sin30⁰

value of

$\sin(45 \degree) = \frac{1}{ \sqrt{2} }$

$\cos(30 \degree) = \frac{ \sqrt{3} }{2}$

$\cos(45 \degree) = \frac{1}{ \sqrt{2} }$

$\sin(30 \degree) = \frac{1}{2}$

put the value

$( \frac{1}{ \sqrt{2} } \times \frac{ \sqrt{3} }{2} ) - ( \frac{1}{ \sqrt{2} } \times \frac{1}{2} )$

$\frac{ \sqrt{3} }{2 \sqrt{2} } - \frac{1}{2 \sqrt{2} }$

$\frac{( \sqrt{3} - 1) }{2 \sqrt{2} }$

value of sin15⁰

$\huge{ \frac{( \sqrt{3} - 1)}{2 \sqrt{2} } }$