value of sinA+sin3A+sin5A +sin7A
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SIN7A+SINA+SIN5A+SIN3A
(2SIN7A+A/2COS7A-A)+ (2SIN5A+3A/2COS5A-3A)
2SIN4ACOS3A+ 2SIN4A+COSA
2SIN4A(COS3A+COSA)
2SINA(2COS3A+A/2COS3A-A)
2SINA(2COS2ACOSA)=0
(2SIN7A+A/2COS7A-A)+ (2SIN5A+3A/2COS5A-3A)
2SIN4ACOS3A+ 2SIN4A+COSA
2SIN4A(COS3A+COSA)
2SINA(2COS3A+A/2COS3A-A)
2SINA(2COS2ACOSA)=0
siddhu96:
for I r inconvinence
u r
and answer is correct
just some more steps
^.^
1-sin^2A means
cosA
cos²a
kk
what is final ans
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