Math, asked by numanansari927869230, 5 months ago

value of tan^2thita.sec^2thita(cot^2 thita-cos^2 thita)=

Answers

Answered by devangnivasava
1

Answer:

1

Step-by-step explanation:

tan^2theta sec^2theta(cot^2 theta -cos^2 theta)

=( tan^2 theta sec^2 theta cot^2 theta) - (tan^2 theta sec^2 theta cos^2 theta)

= (tan^2theta sec^2 theta 1/tan^2 theta) -( tan^2 theta 1/cos^2theta cos^2 theta)

= sec^2 theta - tan^2 theta

= 1

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