Value of tan15degree ?
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Answered by
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tan(15) =
sin(15) / cos(15) =
sin(45 - 30) / cos(45 - 30) =
[ sin(45)cos(30) - sin(30)cos(45) ] / [ cos(45)cos(30) + sin(45)sin(30)]
Since sin(45) = cos(45) = √2/2, you can just factor that out from the top and bottom
[ cos(30) - sin(30) ] / [ cos(30) + sin(30)]
[ √3/2 - 1/2 ] / [ √3/2 + 1/2]
(√3 - 1) / (√3 + 1)
(√3 - 1)^2 / (√3+1)(√3 - 1)
(√3 - 1)^2 / (3 - 1)
(3 - 2√3 +1) / 2
=2 - √3
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Answered by
1
Let us use the Half Angle formula to solve this.
tan (∅/2) = sin∅/(1+cos∅)
In this question, the angle given is 15° = (30/2)°
Inputting this in the Half Angle Formula, we get:
tan(30/2) = sin(30/2) ÷ {1 + cos(30/2)} ---------------- (i)
We know Sin30 = 1/2 and Cos30=(√3)/2. Inputting these values in (i), we get the value of tan (30/2) = 1/2 ÷ {1 + (√3/2)} = 1 / (2 + √3)
Value of Tan15 = 0.268
tan (∅/2) = sin∅/(1+cos∅)
In this question, the angle given is 15° = (30/2)°
Inputting this in the Half Angle Formula, we get:
tan(30/2) = sin(30/2) ÷ {1 + cos(30/2)} ---------------- (i)
We know Sin30 = 1/2 and Cos30=(√3)/2. Inputting these values in (i), we get the value of tan (30/2) = 1/2 ÷ {1 + (√3/2)} = 1 / (2 + √3)
Value of Tan15 = 0.268
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