Value of (x+1/x) whole square.
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Answer:
(1-x)² can also be written as (1-x)(1-x)
Using binomial multiplication, we can evaluate this as follows.
(1-x)(1-x) = [1(1-x)] - [x(1-x)]
= (1-x) - (x-x²)
= 1-x-x+x²
= 1–2x+x²
= x²-2x+1
Hence, (1-x)² = x²-2x+1.
or
( 1-x )whole square
=(1-x ) × (1-x )
=1-x -x +x2
=1 -2x + x2
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