Math, asked by karthikajyothi53414, 7 months ago

Value of (x+1/x) whole square.

Answers

Answered by Yashicaruthvik
3

Answer:

(1-x)² can also be written as (1-x)(1-x)

Using binomial multiplication, we can evaluate this as follows.

(1-x)(1-x) = [1(1-x)] - [x(1-x)]

= (1-x) - (x-x²)

= 1-x-x+x²

= 1–2x+x²

= x²-2x+1

Hence, (1-x)² = x²-2x+1.

or

( 1-x )whole square

=(1-x ) × (1-x )

=1-x -x +x2

=1 -2x + x2

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