Math, asked by leendoboro8, 9 months ago

value of x^3+3y^2 x^2 if x=3,y=2?​

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Answered by varunreddy49
0

Answer:

The Given Equation is

✓3y=y+2

✓3y-y=2

✓2y=2

✓y=2/2=1

Then the value of 2y=2x1=2

Answered by Anonymous
2

\sf\large{\underline{Question:-}}

if x = 3 & y = 2 then find the value of \bf x^3 + 3y^2 x^2

\sf\large{\underline{Given:-}}

  • x = 3
  • y = 2

Substitute these given value In the equation

\bf → x^3 + 3y^2 x^2

\bf → 3^3 + 3 × 2^2 × 3^2

\bf → 27 + 3 × 4 × 9

 \bf → 27 + 108

\bf → 135

\sf\large{\underline{Hence:-}}

  • \bf Value\:of\: x^3 + 3y^2 x^2 \: is = 135
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