Math, asked by shubhdhapanwar28, 2 months ago

value of x
(4/7)^-3×(16/49)^-1= (4/7)^x-1​

Answers

Answered by Sagar9040
2

value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​value of x

(4/7)^-3×(16/49)^-1= (4/7)^x-1​

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