value of x and y in x+y/xy=7 and 3x +2y /xy =17
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Answer:
3x/xy +2y/xy=17
3/y+2/x=17
x/xy +y/xy=7
1/y+1/x=7
let assume 1/x=a,1/y=b
a+b=7,
2a+3b=17,
slove above equation
a=4,b=3
then x=1/4,y=1/3
Answered by
1
Given : (x + y)/xy = 7 , (3x + 2y)/xy = 17
x and y are not equal to zero
To Find : x and y
Solution:
(x + y)/xy = 7
=> x + y = 7xy Eq1
(3x + 2y)/xy = 17
=> 3x + 2y = 17xy Eq2
Eq2 - 2 * Eq1
=> x = 3xy
=> 1 = 3y
=> y = 1/3
Eq2 - 3 * Eq1
=> -y = -4xy
=> x = 1/4
x = 1/4 and y = 1/3
Learn More:
Solve the following x+y/xy=5 and x-5/xy=7
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