value of x³+7x²-x+16 where x=1+2i
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Answer:
x=1+2i
x−1=2i
(x−1)
2
=4i
2
x
2
−2x+1=−4
x
2
−2x+5=0
Therefore, x
3
+7x
2
−x+16=x(x
2
−2x+5)+9(x
2
−2x+5)+(12x−29)
=x(0)+9(0)+12x−29
=12(1+2i)−29=−17+24i
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