Question

value of xcube+4xsquare-px+8 is exactly divisible by (x-2)

Answer 1

Answer:

(x-2) is factor of p(X)

Then 2 is the factor of p(X)

p(X)=x^3+4x^2-px+8

p(2)=(2)^3+4(2)^2-2p+8

0=8+4(4)-2p+8

0=8+16+8-2p

32-2p=0

32=2p

2p=32

p=16

.........

Answer 2

Answer:

p=16. ................