vanadium orbital notation and condensed orbital notation
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Explanation:I am learning about electron configurations and I came across the "exceptions" of Cr and Cu where electrons actually half fill the d orbitals instead of the expected s orbitals. I thought maybe vanadium would do the same, but my textbook gives the answer of an electron configuration exactly following the Aufbau principle.
I've attached a picture of my drawing for the textbook answer and what I had thought might happen — could someone explain why vanadium is not an "exception" like chromium or copper?
Orbital Diagram
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