Vant hoff factor of 0.01M aqueous solutions of ch3cooh
Answers
Answered by
0
Answer:
1
Explanation:
since only 1 replaceable hydrogen
Answered by
0
Answer:
Given : i=1.04
we know i=1+α(n−1)
Here n=2, so i=1+α
α=0.04
[H
+
]=Cα=0.01(0.04)=4×10
−4
pH=−log[H
+
]=−log[4×10
−4
]=4−log4
pH=4−0.6=3.4
Explanation:
Similar questions