Question

vapour density of a gas is 8 . At STP mass of 11.2 litre of this gas is

Answer 1

at stp., 1 mole of gas ----------->22.4 L

"x" mole of gas-----------> 11.2L

x=(11.2/22.4)=0.5 moles.


vapour density =(molecular mass/2)

molecular mass=2* vapour density

molecular mass =2*8=16 Amu.


now...,


1 mole ----------------------->16 amu

0.5 mole----------------------->"y" amu


y=(0.5*16)=8 amu.



so, at 11.2L ,STP,,, mass will be=8amu.


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Answer 2

Vapour density of a molecule is equal to half its molecular mass. So the gas’ molecular mass would be 22.4 .
So the gas has 10/22.4 moles. 1 mole occupies 22.4 L at STP. So 10/2.24 moles would occupy (10/22.4)*22.4 = 10 L at STP.

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