Question

Vapour density of gas if it's density is 0.178g/L at NTP is

Answer 1

"When the Vapour density of gas is at 0.178g/L at NTP can be calculated as

Vapour density = mass of n molecules of gas or the mass of n molecules of hydrogen.

Vapour density = molar mass of gas / molar mass of H2

Vapour density = molar mass of gas / 2.016

1L = 0.178g

Hence 22.4 L = 0.178 x 22.4 = 3.9872

Molecular mass = 3.9872

Vapour density = molecular mass /2 = 3.9872/2 = 1.9936

"

Answer 2

P1/d1×T1 = P2/d1×T2

Value of pressure at NTP =760mmhg

And temperature= 273k

Hence, P1=760 ,P2= 740

D1=0.1782g per lit , T1 273k

T2= 300k

760/0.1782×273. = 740 /d2×300

D2 = 0.1782×740×273/300×760

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