Vapour density of metal chloride is 77 Equivalent weight of metal is 3 then the atomic weight will be
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Vapour density of metal chloride is 77, so its molecular weight is 154
Now let us assume that there are 4 chlorine atoms in the metal chloride(MCl₄),
then the total weight of chlorine in the compound is 4 x 35.5 = 142
therefore the weight of metal in the compound is 154 - 142 = 12
now, n-factor of metal is 4(as there are 4 chlorine atoms in its compound)
Hence the Equivalent weight of the metal is 12/4 = 3(as given)
Therefore since our assumption is satisfying the condition that equivalent weight of metal is 3, our assumption (MCl₄) is correct.
The atomic weight of the metal is 12
Now let us assume that there are 4 chlorine atoms in the metal chloride(MCl₄),
then the total weight of chlorine in the compound is 4 x 35.5 = 142
therefore the weight of metal in the compound is 154 - 142 = 12
now, n-factor of metal is 4(as there are 4 chlorine atoms in its compound)
Hence the Equivalent weight of the metal is 12/4 = 3(as given)
Therefore since our assumption is satisfying the condition that equivalent weight of metal is 3, our assumption (MCl₄) is correct.
The atomic weight of the metal is 12
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it is the answer of the question
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