Vapour density of pcl5 is 104.25 at T degree Celsius . Then degree of dissociation of Pcl5 is?
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initial vapor density/vapor density at equilibrium=mole at equilibrium/initial mole
PCL₅→PCL₃ +CL₂
initial concentration=C
concentration of PCL₃= C-Cx
(x is the degree of dissociation)
PCL₃=Cx
CL₂=Cx
total mole at equilibrium= C +Cx
initial mole=C'
So,
C +Cx/C' = 104.25/104.25
1 + x =1
x = 0
PCL₅→PCL₃ +CL₂
initial concentration=C
concentration of PCL₃= C-Cx
(x is the degree of dissociation)
PCL₃=Cx
CL₂=Cx
total mole at equilibrium= C +Cx
initial mole=C'
So,
C +Cx/C' = 104.25/104.25
1 + x =1
x = 0
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