Chemistry, asked by dimpiVaishika, 1 year ago

Vapour density of pcl5 is 104.25 at T degree Celsius . Then degree of dissociation of Pcl5 is?

Answers

Answered by sharinkhan
60
initial vapor density/vapor density at equilibrium=mole at equilibrium/initial mole
PCL
₅→PCL +CL

initial concentration=C
concentration of PCL
= C-Cx
(x is the degree of dissociation)
PCL
=Cx
CL
=Cx

total mole at equilibrium= C +Cx
initial mole=C'
So,

C +Cx/C' = 104.25/104.25
1 + x =1
x = 0
Answered by preetykumari1006
16

Answer:

68%

Explanation:

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