Question

Vapour density of pcl5 is 104.25 at T degree Celsius . Then degree of dissociation of Pcl5 is?

Answer 1

initial vapor density/vapor density at equilibrium=mole at equilibrium/initial mole
PCL₅→PCL₃ +CL₂

initial concentration=C
concentration of PCL₃= C-Cx
(x is the degree of dissociation)
PCL₃=Cx
CL₂=Cx

total mole at equilibrium= C +Cx
initial mole=C'
So,

C +Cx/C' = 104.25/104.25
1 + x =1
x = 0

Answer 2

Answer:

68%

Explanation: