Question

vapour pressure of a moist gas at 100 °C is 750 mm and aqueous tension at that temperature is 10mm
Then vapour pressure of the dry gas is
(1) 750mm
(2) 760mm
(3) 740mm
(4) 720mm​

Answer 1

Answer:

740 mm

Explanation:

Given Vapour pressure of a moist gas at 100 °C is 750 mm and aqueous tension at that temperature is 10mm

Then vapour pressure of the dry gas is

Given vapour pressure = 750 mm at temperature = 100 degree Celsius

 Aqueous tension = 10 mm

P (moist gas) = p(dry gas) + aqueous tension

P (dry gas) = p (moist gas) – aqueous tension

P (dry gas) = 750 – 10  

P (dry gas) = 740 mm

Answer 2

Vapour pressure of the dry gas is 740 mm Hg

Explanation:

According to Dalton's law, the total pressure of a mixture of gases is the sum of individual pressures exerted by the constituent gases.

$p_{total}=p_A+p_B$

Thus $p_{moist gas}=p_{H_2O}+p_{dry gas}$

Given: $p_{moist gas}=750 mmHg$

$p_{H_2O}$ = 10 mm Hg

$750=10+p_{dry gas}$

$p_{dry gas}=740mm Hg$

Thus vapour pressure of the dry gas is 740 mm Hg

Learn more about Dalton's law

https://brainly.com/question/9211800

https://brainly.com/question/11913050