Fig. 2.1 shows a car travelling at 30 m/s on a level road. At this speed the car has to overcome a total force of 600 N opposing the car. (a) (i) Calculate the distance travelled by the car in 10 s. (ii) State the value of the driving force produced by the engine for a steady speed of 30 m/s. (b) Explain why the car slows down when it climbs a hill, even though the driving force is unchanged.(c) While on the level road and travelling at 30 m/s, the driving force becomes zero. The mass of the car is 800 kg. Calculate the deceleration of the car.
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Answer:
this speed the car has to overcome a total force of 600 N opposing the car. (a) (i) Calculate the distance travelled by the car in 10 s. (ii) State the value of the driving force produced by the ...
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Answer:Fig. 2.1 shows a car travelling at 30 m/s on a level road. At this speed the car has to overcome a total force of 600 N opposing the car. ... More
Answer:
ai) 300m (aii)600N c)-0.75m/s-2
Explanation:
ai)v = s/t
s = vt = (30 ms-1
)(10 s)
s = 300 m (s.f. may be 1, 2 or 3 since anything before decimal point is insignificant)
aii) 600 N
(constant velocity, hence no net forces, therefore driving force must be balanced by
opposing forces)
b)This is because the NET FORCE acting on the vehicle is in the OPPOSITE direction
compared to that of the velocity of the vehicle. This results in the velocity decreasing.
(please turn to back for detailed explanation)
c)F = ma
(− 600 N) = (800 kg) a
a = − 0.75 ms-2 (s.f. not critical)