Question

Vapour pressure of an aqueous solution of 1molal glucose solution at 100degree centigrade

Answer 1

Molarlity =W2Mw2×W1×1000

where W2 = mass of solute in grams,

W1 = mass of solvent in grams

1.0=W2×1000Mw2×W1

(KW1=K')=1.01000=0.001

Applying Raoult's law for dilute solution,

P∘−PSP∘=W2Mw2×W1×Mw1 [Mw1=18]

760−PS760=0.001×18

=760−13.68

746.32mmHg

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