vapour pressure of chloroform and di-chloro-methane are 200mmHg and415mmHg calculate a vapour pressure of solution by mixing 25. 5 g of chloroform and 40g of di-chloro-methane also find mole fraction of both in vapour phase
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Molar mass of chloroform ChCl3= (1*12)+(1*1)+(3*35.5)=119.5g/mol
Molar mass of dichloromethane Ch2Cl2=(1*12)+(2*1)+(2*35.5)=85g/mol
Moles of ChCl3=25.5/119.5=0.213mol
Moles of Ch2Cl2=40/85=0.47mol
Total number of moles=0.683 mol
Mole fraction of Ch2Cl2=0.47/0.683=0.688
Mole fraction of ChCl3=1-0.688=0.312
Vapour pressure of the solution can be found out using the following equation:Ptotal=P1+(P2-P1)X2
=20+(415-200)*0.688
=347mmHg
Molar mass of dichloromethane Ch2Cl2=(1*12)+(2*1)+(2*35.5)=85g/mol
Moles of ChCl3=25.5/119.5=0.213mol
Moles of Ch2Cl2=40/85=0.47mol
Total number of moles=0.683 mol
Mole fraction of Ch2Cl2=0.47/0.683=0.688
Mole fraction of ChCl3=1-0.688=0.312
Vapour pressure of the solution can be found out using the following equation:Ptotal=P1+(P2-P1)X2
=20+(415-200)*0.688
=347mmHg
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