Math, asked by prathmeshbansode1986, 1 month ago

वर्गार सावली
25
व पची माया
20
का​

Answers

Answered by swapnamatoor
1

Step-by-step explanation:

Here, Principal (P) = Rs. 10800, Time (n) = 3 years Rate of interest (R) = 12\ \frac{1}{2}\%=\frac{25}{2\%}12

2

1

%=

2%

25

Amount(A) = P\left(1+\frac{R}{100}\right)^nP(1+

100

R

)

n

= 10800\left(1+\frac{1}{8}\right)^3=10800\left(\frac{9}{8}\right)^3(1+

8

1

)

3

=10800(

8

9

)

3

= 10800\times\frac{9}{8}\times\frac{9}{8}\times\frac{9}{8}10800×

8

9

×

8

9

×

8

9

= Rs. 15,377.34

Compound Interest (C.I.) = A – P

= Rs. 10800 – Rs. 15377.34 = Rs. 4,577.34

(b) Here, Principal (P) = Rs. 18,000, Time (n) = 2\ \frac{1}{2}2

2

1

years, Rate of interest (R) = 10% p.a.

Amount(A) = P\left(1+\frac{R}{100}\right)^nP(1+

100

R

)

n

= 18000\left(1+\frac{10}{100}\right)^2=18000\left(1+\frac{1}{10}\right)^218000(1+

100

10

)

2

=18000(1+

10

1

)

2

= 18000\left(\frac{11}{10}\right)^2=18000\times\frac{11}{10}\times\frac{11}{10}18000(

10

11

)

2

=18000×

10

11

×

10

11

= Rs. 21,780

Interest for \frac{1}{2}

2

1

years on Rs. 21,780 at rate of 10% = \frac{21780\times10\times1}{100}

100

21780×10×1

= Rs. 1089

Total amount for 2\ \frac{1}{2}2

2

1

years.

= Rs. 21,780 + Rs. 1089 = Rs. 22,869

Compound Interest (C.I.) = A – P

= Rs. 22869 – Rs. 18000 = Rs. 4,869

(c) Here, Principal (P) = Rs. 62500, Time (n) = 1\ \frac{1}{2}=\frac{3}{2}1

2

1

=

2

3

years = 3 years

Rate of interest (R) = 8% = 4% (compounded half yearly)

Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+

100

R

)

n

= 62500\left(1+\frac{4}{100}\right)^2(1+

100

4

)

2

= 62500\left(1+\frac{1}{25}\right)^3(1+

25

1

)

3

= 62500\left(\frac{26}{25}\right)^3(

25

26

)

3

= 62500 \times\frac{26}{25}\times\frac{26}{25}\times\frac{26}{25}×

25

26

×

25

26

×

25

26

= Rs. 70,304

Compound Interest (C.I.) = A – P

= Rs. 70304 – Rs. 62500 = Rs. 7,804

(d) Here, Principal (P) = Rs. 8000, Time (n) = 1 years = 2 years (compounded half yearly)

Rate of interest (R) = 9% = \frac{9}{2}\%

2

9

% (compounded half yearly)

Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+

100

R

)

n

= 8000\left(1+\frac{9}{2\times100}\right)^28000(1+

2×100

9

)

2

= 8000\left(1+\frac{9}{200}\right)^28000(1+

200

9

)

2

= 800\left(\frac{209}{200}\right)^2800(

200

209

)

2

= 8000\times\frac{209}{200}\times\frac{209}{200}8000×

200

209

×

200

209

= Rs. 8,736.20

Compound Interest (C.I.) = A – P

= Rs. 8736.20 – Rs. 8000

= Rs. 736.20

(e) Here, Principal (P) = Rs. 10,000, Time (n) = 1 years = 2 years (compounded half yearly)

Rate of interest (R) = 8% = 4% (compounded half yearly)

Amount (A) = P\left(1+\frac{R}{100}\right)^nP(1+

100

R

)

n

= 10000\left(1+\frac{4}{100}\right)^210000(1+

100

4

)

2

= 10000\left(1+\frac{1}{25}\right)^210000(1+

25

1

)

2

= 10000\left(\frac{26}{25}\right)^210000(

25

26

)

2

= 10000\times\frac{26}{25}\times\frac{26}{25}10000×

25

26

×

25

26

= Rs. 10,816

Compound Interest (C.I.) = A – P

= Rs. 10,816 – Rs. 10,000 = Rs. 816

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