2^33 is divided by 17 then the remainder according to cyclicity
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Answer:
17 can be written as 24+1. So, we have to create factors of 24+1 to solve this question. Thus, remainder is 2.
Answered by
0
17 can be written as 24+1. So, we have to create factors of 24+1 to solve this question. Thus, remainder is 2.
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