Question

Varify the relation between the zeros and the co-efficents.
4usquareplus 18u ???

Answer 1

Relation Between Coefficients And Zeros Of A Polynomial

i.e. 4x – 1 = 0 gives x = \frac 14 and x – 2 = 0 gives x = 2. ... In general, if α and β are the zeros of the polynomial P(x)= ax^2+bx+c,a≠0, then (x – α) and (x – β) are the factors of P(x).

Answer 2

Answer: The given polynomial : 4u^2 + 18u.

4u^2 + 18u + 0 = 0

2u(2u + 9) = 0

2u = 0 or 2u + 9 = 0

u = 0 or u = -9/2

Comparing the equation

with ax^2 + bx + c,

a = 4 , b = 18 , c = 0

Let the two zeroes be p and q .

p + q = -b/a

p + q = 0 + -9/2 = -9/2

-b/a = -(18/4) = -9/2

pq = c/a

pq = 0 × -9/2 = 0

c/a = 0/4 = 0

Therefore,

p + q = -b/a

pq = c/a

H.p.

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