vase 1 contains 2 white and 4 black balls and vase 2 contains 4 white and 4 black balls if a ball is drawn out at random from one of the two vases what is the probability that it is a white ball
Answers
Answered by
4
Answer:
2+4=6and4+4=8
and total no. of balls=14
therefore,
probability of getting a white ball is
6÷14=~0.43
Answered by
3
Answer:
5/12.
Explanation:
The total number of balls in the vase 1 is given as 4+2=6 so the probability of getting white ball from vase 1 will be 2/6 = 1/3. For the second vase the total number of balls is 4+4=8 balls and the probability of getting a white ball is 4/8 = 1/2.
So, the probability of getting a white ball from both of the bags at a random will be 1/2*1/2 + 1/3*1/2 which on solving we will get that 5/12. Since there are 2 bags hence we take 1/2 for each bag.
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