vector A=2i+pj+qk, and vector B=5i+7j+3k. If A || B, p and q are, respectively.
Answers
Answered by
15
Answer:
Everything in B will be 2.5 times everything in A because they are parallel and 5/2 = 2.5. So, p= 14/5 and q=6/5.
Explanation:
{\vec{A}} = 2 \widehat{i} + p\widehat{j} + q\widehat{k} and {\vec{B}} = 5 \widehat{i} + 7\widehat{j} + 3\widehat{k}.
Since they are parallel, |A×B| = 0
\implies \left | [2 \widehat{i} + p\widehat{j} + q\widehat{k}] \times [5 \widehat{i} + 7\widehat{j} + 3\widehat{k} ]\right | = 0
\implies \left | (3p-7q) \widehat{i} + (5q-6)\widehat{j} + (14-5p)\widehat{k}\right | = 0
So, (3p - 7q) = 0 ; (5q - 6) = 0. ; (14 - 5p) = 0
Hence, p = \frac{14}{5} & q = \frac{6}{5}
THANKS
sarthakhandelwal:
how to simplify bro?
Answered by
11
Answer:by using shortcut
Explanation:14/5 and 6/5
Attachments:
Similar questions