Question

Vector A has magnitude 2 and vector B has magnitude 3. What is the angle between
A and B if |AXB|= 6

Answer 1

Answer:

your answer is $\pi /2$

Explanation:

|A X B|=ABsin(x)

where x is the angle between them

ABsin(x)=6

3 x 2 sin(x)=6

sin(x)=1

x=$\pi /2$

this is your required  answer.