Question

vector a having magnitude 5 units lies in xy plane and points ina direction 120 from direction of increasing x .vector b had magnitude of 9 units and points along z axis what is magnitude of cross product of axb=

Answer 1

Answer:

((45√3)/2)i

Explanation:

first break vector a into its components.

5 cos(120) will give you x-component.

5 sin(120) will give you the y-component.

Get the value of vector a by combining these components (-5/2)i+(5√3/2)j

vector b is 9k.

now take the cross product using the determinant form.

Answer 2

Answer:

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Explanation:

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